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we will see how to find count of all the duplicate records in the table. Following query demonstrates usage of GROUP BY, HAVING, ORDER BY in one query and returns the results with duplicate column and its count in descending order.
SELECT YourColumn, COUNT(*) TotalCount
FROM YourTable
GROUP BY YourColumn
HAVING COUNT(*) > 1
ORDER BY COUNT(*) DESC
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Duplicate Delete Rows
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The table must have identity column, which will be used to identify the duplicate records. Table in example is has ID as Identity Column and Columns which have duplicate data are DuplicateColumn1, DuplicateColumn2 and DuplicateColumn3.
DELETE
FROM MyTable
WHERE ID NOT IN
(
SELECT MAX(ID)
FROM MyTable
GROUP BY DuplicateColumn1, DuplicateColumn2, DuplicateColumn2)
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Query to Retrieve the Nth Maximum value-------------------------------------------------------------------------------------------------
How to get 1st, 2nd, 3rd, 4th, nth topmost salary from an Employee table
The following solution is for getting 6th highest salary from Employee table ,
SELECT TOP 1 salary
FROM (
SELECT DISTINCT TOP 6 salary
FROM employee
ORDER BY salary DESC) a
ORDER BY salary
You can change and use it for getting nth highest salary from Employee table as followsSELECT TOP 1 salary
FROM (
SELECT DISTINCT TOP n salary
FROM employee
ORDER BY salary DESC) a
ORDER BY salary
where n > 1 (n is always greater than one)
USE AdventureWorks;
GO
SELECT TOP 1 Rate
FROM (
SELECT DISTINCT TOP 4 Rate
FROM HumanResources.EmployeePayHistory
ORDER BY Rate DESC) A
ORDER BY Rate
GO--------------------------------------------------------------------------------------------------
